ADDENDUM
TO TRONIX BOOK 2 Version 2.0
(Green Cover with Red Stripe)
NOTE: BEFORE YOU START
THIS WORKBOOK, MARK THESE CORRECTIONS IN YOUR TRONIX 2 BOOK.
Page 2b - a very important correction is necessary in
the Truth Table for the ‘AND’ gate in column 1 of this page. It should read, from top to bottom, 000,010,
100,111. Also, in column 2 there is a
font error in the middle of column 2 where it says, “Note: The dot (there is a
funny Y with two lines through it. It
should be a dot like this. •
Page 3b - in column
2 under the sub-title EXPERIMENT, the last sentence in Part 2 should read
“Fill-in Q as a ‘1’ on Line 4 (not Line 1) of the Truth Table on the right.
Page 7b, the formula at the top of the right hand column
should have a dot to indicate multiply between the R1 and the C1.
Page 14a - in the box labeled ‘Pinout of the
Seven-Segment Display’ the Y’s with the lines through them should not appear in
the diagram. They were meant to be dots
like this •.
Page 18b - in the second column there is a diagram of the
chip and a Table of Inputs and outputs.
It says “Multiplexer” but it should say “The Demultiplexer and
its Output Switches Table”.
Page 19a - Please
note that this particular experiment requires a 9 volt alkaline battery to make
it work correctly because it draws a lot of current from the battery. (Also, at one time we sent some 4051 chips
made by HEF. This particular brand of IC will not work in this experiment. If you have these, please ask us for
replacements.)
Also, there is an error on the pictorial diagram of
19a. R6 is shown plugged into the
negative bus but it should be plugged into the positive bus line. The schematic is correct.
Page 20b - In the first column, under 555 TIMER IC, the
last sentence should read, “will alternate if there is a pulse.”
Page 22a, on the circuit board
PICTORIAL DIAGRAM the + and – signs in the lower left hand corners need to come
up like on the right hand lower corner.
Also, be sure to use NE555 for this experiment. For some reason, other 555s do not work.
Page 23b, the first paragraph
after CIRCUIT DESCRIPTION is incorrect and should be crossed out. The actual reason that it is 50/50 is
because the output of pin 6 on the 4029 turns on and off every other pulse,
thus 50-50 chance you will have the LED lit up.
Page 27a, there is a label of 560 ohms along the lower edge
of the Solderless circuit board that does not refer to any part and does not
need to be there.
Page 27b, in the paragraph under 4029 COUNTER the last word
is Demultiplexer and it should be BINARY COUNTER instead.
Page 28b, on the third column, which is the INVENTORY of
parts, it shows a Pushbutton Switch near the bottom, this should really be a
picture of a Potentiometer.
Page 29b, in the first column, under the heading 555 TIMER
CHIP AS A ‘CLOCK’, there are some funny characters on either end of the work
CLOCK. They were supposed to be single
quote marks but the computer program changed the font on us.
Page 30a, there is an extra wire on the schematic connecting
Pin 1 of the 4029 to Pin 6 on the 4511.
This wire should not be there.
Page 33a and 33b.
Two things are wrong.
(1) The correct
spelling of Schmitt is with two of the letter T, not DT.
(2) Also, more
important, the output of the Schmitt Trigger should be into an IC like the 4011
and not to an LED as we did. Wire a
4011 IC up so that both inputs on one of the gates is connected to Pin 3 on the
4093 and the output of the 4011 is connected to an LED and a resistor with the
cathode of the LED toward ground.
This way when there is a ‘HI’ on the output of the 4093 the
LED will light up and when there is a ‘LO’ it will not be lit. Now when you measure the voltage at which it
‘snaps’ to ‘HI’ and the voltage at which it ‘snaps’ to ‘LO’ they will be
right.
The ‘snap’ voltages we show are for exactly 9 volts. Measure the battery voltage and use the
formula (9 volts divided by 4.72 volts) = (your battery voltage divided by
X). Solve for X and that will be the
‘snap’ voltage on the way up from zero to nine.
The ‘snap’ voltage on the way down from nine volts to zero
volts is found by the formula (9 volts divided by 3.87 volts) = (your battery
voltage divided by X). Solve for X.
If you notice any other changes that need to be made, please
contact me at: Gary Gibson, Gibson Tech Ed, 1-800-422-1100 or email
gary@GibsonTechEd.com
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